∆A25° ,∆Bx° ,∆C30° find the x value
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SREEKARRAO:
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angle b = ×
angle a + angle b + angle c = 180
25 + × + 30 =180
55+×=180
×=180-55
× = b =125
it's solved through angle sum property of triangle
angle a + angle b + angle c = 180
25 + × + 30 =180
55+×=180
×=180-55
× = b =125
it's solved through angle sum property of triangle
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