Question

( a²b - ab² )² using identity
Plz help me plz plz​

Answer 1

Step-by-step explanation:

Since

A³-B³-AB²+A²B=0

⇒ (A³-AB²)+(A²B-B³)=0

⇒ A(A²-B²)+(A²-B²)B=0

and

A³-B³-AB²+AB²=0

⇒ (A³-AB²)+(AB²-B³)=0

⇒ A(A²-B²)+(A-B)B²=0

We have

A(A²-B²)+(A²-B²)B=0=A(A²-B²)+(A-B)B²

⇒ (A²-B²)B=(A-B)B².

Therefore

det(A²-B²)det B = det(A-B)det B²

det(A²-B²) = (1/(detB))det(A-B)det B², if det B≠0

Hence

det(A²-B²) = det(A-B)det B, if det B≠0