Question

a²b(b²-2a)+a(b_a²b)_b(a+2a³)​

Answer 1

Answer:

Step-by-step explanation:

First open all the brackets.

a²b(b²-2a)+a(b-a²b)-b(a+2a³)​

= a²b³ - 2a³b + ab + a³b - ab - 2a³b

= a²b³ - 3a³b

= a²b(b² - 3a)