Math, asked by Sristi6541, 11 months ago

(a²b,-b²a)² evaluate using identities

Answers

Answered by DevyaniKhushi
24

 {( {a}^{2}b -  {b}^{2}a )}^{2}  \\  \\  {( {a}^{2}b )}^{2}  +  {( {b}^{2}a )}^{2}  - 2( {a}^{2} b)( {b}^{2}a ) \\  \\  {a}^{4} {b}^{2}  +  {b}^{4} {a}^{2}  - 2( {a}^{3} {b}^{3} ) \\  \\ {a}^{4} {b}^{2}  +  {b}^{4} {a}^{2}  - {2a}^{3} {b}^{3}

Answered by amankumaraman11
7

  \bf  \huge \bigstar \:  \: [ {a}^{2}b -  {b}^{2}a  ]^{2}  \\  \\  \tt \implies \:  {( {a}^{2}b )}^{2}  +  {( {b}^{2}a )}^{2}  - 2({a}^{2}b)({b}^{2}a) \\  \tt \implies \: \red{  {a}^{4} {b}^{2}  +  {b}^{4}  {a}^{2}  - 2 {a}^{3}  {b}^{3} }

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