Question

a²b c³ = 5³ and ab² = 5⁶ then abc =??

Answer 1

Answer:

Step-by-step explanation:

⇒ a²bc³(ab²) = 25(5)

⇒ a²(a) * b(b²) * c³ = 125

⇒ a²(a¹) * b¹(b²) * c³ = 125

\sf  \implies a^{2 + 1} \times  b^{2 + 1} \times c^3 = 125

\bf  \because  a^{m} \times a^n = a^{mn}  

⇒ a³ * b³ * c³ = 125

⇒ (abc)³ = 125

\bf  \because  a^{n} \times b^n = (ab)^{n}  

\sf  \implies abc =  \sqrt[3]{125}  

\sf  \implies abc =  \sqrt[3]{ {5}^{3} }  

\sf  \implies abc =5

\sf  \therefore abc =5

\Huge{\boxed{ \sf abc = 5}}

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Answer 2

Step-by-step explanation:

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