(a²b²- 2ab + 4)(a + 2)
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Sum of the three terms = a - d + a + a + d = 3a
3a = 33
a = 11
Also, from the given information, we have:
(a - d)(a + d) = a + 29
a2 - d2 = 11 + 29 = 40
121 - d2 = 40
d2 = 81
d = 9
Thus, the AP is
2, 11, 20, … or 20, 11, 2, …
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