Question

a2b2-6abc+9c2 factorise

Answer 1

Hi there !!

Given,
to factorise a²b² - 6abc + 9c²

It is seen that the algebraic identity (a-b)² = a²- 2ab + b² will be used

Therefore,

$(ab) {}^{2} - 2(ab)(3c) + (3c) {}^{2}$

$= (ab - 3c) {}^{2} \\ = (ab - 3c)(ab - 3c)$
is the answer

Answer 2

Answer:

(ab+3c) (ab+3c) will be the correct answer.