a²b²=c(a²+b²)solve this to get 1/c=1/a²+1/b²
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a^2b^2/(a^2+b^2)
1/c=a^2+b^2/a^2b^2
=1/b^2+1/a^2
1/c=a^2+b^2/a^2b^2
=1/b^2+1/a^2
manisha4812:
tnq
Answered by
1
HOLA MATE !!!
HOPE THIS HELPS YOU...
Answer:
We can solve this by cross multiplying and converting it to the p/q form.
Step-by-step explanation:
=> a²b² = c (a² + b²)
=> a²b² /c = a² + b²
=> 1/c = a²/(a²b²) + b²/(b²c²)
Now we can cancel a² ,b² from both numerator and denominator of the above equation,
=> 1/c = 1/b² + 1/a²
or 1/c = 1/a² + 1/b²
Hence, we have proved that ,
1/c = 1/a² + 1/b²
THANK YOU FOR THE WONDERFUL QUESTION...
#bebrainly
HOPE THIS HELPS YOU...
Answer:
We can solve this by cross multiplying and converting it to the p/q form.
Step-by-step explanation:
=> a²b² = c (a² + b²)
=> a²b² /c = a² + b²
=> 1/c = a²/(a²b²) + b²/(b²c²)
Now we can cancel a² ,b² from both numerator and denominator of the above equation,
=> 1/c = 1/b² + 1/a²
or 1/c = 1/a² + 1/b²
Hence, we have proved that ,
1/c = 1/a² + 1/b²
THANK YOU FOR THE WONDERFUL QUESTION...
#bebrainly
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