Math, asked by shyamraghuwanshi3381, 1 year ago

a²b²=c(a²+b²)solve this to get 1/c=1/a²+1/b²

Answers

Answered by manisha4812
2
a^2b^2/(a^2+b^2)
1/c=a^2+b^2/a^2b^2
=1/b^2+1/a^2

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Answered by Anonymous
1
HOLA MATE !!!

HOPE THIS HELPS YOU...


Answer:

We can solve this by cross multiplying and converting it to the p/q form.


Step-by-step explanation:

=> a²b² = c (a² + b²)

=> a²b² /c = a² + b²

=> 1/c = a²/(a²b²) + b²/(b²c²)

Now we can cancel a² ,b² from both numerator and denominator of the above equation,

=> 1/c = 1/b² + 1/a²

or 1/c = 1/a² + 1/b²

Hence, we have proved that ,
1/c = 1/a² + 1/b²

THANK YOU FOR THE WONDERFUL QUESTION...

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