Math, asked by bharathkumbham3839, 1 year ago

(⅔a²b²c²+⁴/3ab²c²)÷½abc

Answers

Answered by brunoconti
0

Answer:

Step-by-step explanation:

(2/3 a^2b^2c^2 + 4/3 a b^2c^2)/ (1/2abc) =

(2/3 ab^2c^2)(a +2) / (1/2)abc =

4/3 bc(a + 2)

Answered by adityaaryaas
0

Answer:4abc

Step-by-step explanation:

Please find the attached file.

Attachments:
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