Question

a2b2x2+b2x-a2x-1=0 ...................​

Answer 1

Answer:

a²b²x²+b²x-a²x-1 =0

b²x(a²x+1)-1(a²x+1)=0

(b²x-1)(a²x+1)=0

if b²x-1=0

b²x=1

x=1/b²

if a²x+1=0

a²x=-1

x=-1/a²

Answer 2

Answer:

Step-by-step explanation:

a2b2x2 + b2x - a2x - 1 = 0

or b2x(a2x + 1) - 1(a2x + 1) = 0

or (b2x - 1) (a2x + 1) = 0

or x =  

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