Question

a2x-b2y=a2-2b2
b2x+a2y=b2+2a2
Solve it

Answer 1

Step-by-step explanation:

a²x+b²y= a²-2b²

=> x +b²y/a²= 1 - 2b²/a².............(1)

b²x+a²y= b²+2a²

=> x + a²y/b²= 1+ 2a²/b²............(2)

(1). - (2)

( b²/a² - a²/b²) y= - ( 2b²/a² + 2a²/b²)

=> y= -2 ( b²/a²+a²/b²) / ( b²/a² - a²/b²)

= -2 ( b⁴+a⁴) / ( b⁴- a⁴)

= 2( a⁴+b⁴) / ( a⁴-b⁴)

similarly

x= ( a⁴-b⁴-4a²b²) / (a⁴-b⁴)

= 1 - 4a²b²/(a⁴-b⁴)

x= 1- 4a²b²/ (a⁴-b⁴)

y= 2(a⁴+b⁴) / ( a⁴-b⁴)

Answer 2

Answer:

Solve for x and y using substitution method: a²x - b²y = a² - 2b²; b²x + a²y = b² + 2a²