Question

a2x2-3abx+2b2=0 solve it by completing square method​

Answer 1

Step-by-step explanation:

a^2x^2 - 3abx + 2b^2 =0

Divide the equation by coefficient of x^2

x^2 - 3bx/a + 2b^2/a^2 =0

x^2 - 3bx/a = - 2b^2/a^2

x^2 - 3bx/a + (3b/2a)^2 = - 2b^2/a^2 + (3b/2a)^2

( x - 3b/2a )^2 = -2b^2/a^2 + 9b^2/4a^2

(x - 3b/2a)^2 = b^2/4a^2

x - 3b/2a = +_ (b/2a)

If b/2a is positive, then

x = b/2a + 3b/2a

x = 4b/2a = 2b/a

If b/2a is negative, then

x = 3b/2a - b/2a

x = 2b/2a = b/a