Math, asked by joker3861, 8 months ago

a²x² + (a²+b²)x + b² = 0



Answers

Answered by FateBringer22
3

Answer:

no its not equal

Step-by-step explanation:

none


joker3861: plz
joker3861: thanks dangerous queen thanks lots of love you
Answered by dangerousqueen01
7

Step-by-step explanation:

a²x² + (a²+b²) x + b² = 0

=> a²x² + a²x + b²x + b² = 0

=> a²x (x+1) + b² (x+1) = 0

=> (x+1) (a²x+b²) = 0

Either,

(x+1) = 0

=> x = -1

Or,

(a²x+b²) = 0

=> b² = -a²x

=> b = -a√x

=> -b/a = √x

=> x = b²/a²

or,

=> a²x = -b²

=> a² = -b²/x

=> a = -b√x

=> √x = -a/b

=> x = a²/b²

=> x = b²/a²


dangerousqueen01: like my answer
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