Question

a²x² + (a²+b²)x +b²=0 find the value of x. please tell me this fast i will make ypu brainliest ​

Answer 1

Answer:

Here is your answer

Step-by-step explanation:

a

${a}^{2} {x}^{2} + ( {a}^{2} + {b}^{2} )x + {b }^{2} = 0 \\ = {a}^{2} {x}^{2} + {a}^{2} x + {b}^{2} x + {b}^{2} = 0 \\ = {a}^{2} x(x + 1) + {b}^{2}(x + 1) = 0 \\ = ( {a}^{2}x + {b}^{2} )(x + 1) = 0 \\ = > either \: x + 1 = 0 \\ then \: \: x = - 1 \\ = > either \: {a}^{2} x + {b}^{2} = 0 \\ then \: x = \frac{ - {b}^{2} }{ {a}^{2} }$