Math, asked by bulanditjindal2006, 8 months ago

a³ -0.216 please tell me these​

Answers

Answered by brainliest2008
0

Multiply that by A

So A(I + A + A^2) = AB

So A + A^2 + A^3(=0) = AB

So A + A^2 = AB

I + A + A^2 = B

So A + A^2 = B - I

So, B - I = AB

So (A - I)B = -I

So, B = -(A - I)^(-1)

Edit 1 : Marco Pereira has suggested a far simpler solution.

A + A^2 = AB. Multiply this by A^(-1) on both sides. So, A^(-1)A + A^(-1)*A^2 = A^(-1)*AB. So, I + A = B.

So, we get B = I + A.

Thank you for the suggestion!

825 viewsView 3 Upvoters · Answer requested by Akeel Hussain

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found it on google

Answered by Anonymous
1

if u see it clearly ,

 \sqrt[3]{0.216}  = 0.6

 {a}^{3}  -  {(0.6)}^{3}

using formula

 {x}^{3}  -  {y}^{3}  = (x - y)( {x}^{2}  +  {y}^{2}  + xy)

here,

(a - 0.6)( {a}^{2}  + 0.36 + 0.6a)

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