a3=15 s10=125 find d and a10
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Step-by-step explanation:
a3=a+(n-1)d
=>15=a+(3-1)d
=>15=a+2d ......... (1)
Sn=n/2{2a+(n-1)d}
=>S10=10/2{2a+(10-1)d}
=>125=5(2a+9d)
=>2a+9d=125/5
=>2a+9d=25 .......... (2)
From equation (1) and (2),
a+2d=15 ....×2
2a+9d=25
2a+4d=30
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2a-2a+9d-4d=25-30
=>5d=-5
=>d=-1
Put the value of d in equation (1)
a+2×-1=15
=>a=15+2
=>a=17
Now,
a10=a+(10-1)d
=>a10=17+9×(-1)
=>a10=17-9
=>a10=8
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