Math, asked by Tarushjain, 11 months ago

a³-2√2 b³ solve. djjr​

Answers

Answered by vyasananya057
0

Answer:

use identity a^3-b^3=(a-b)(a^2+ab+b^2)

Step-by-step explanation:

a^3-2√2b^3=(a-2√2b)(a^2+2√2ab+4*2*b^2)

(a-b)(a^2+2√2ab+8b^2)

AS (2√2b)^2 = 2*2*√2*√2*b*b

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