Math, asked by rahul271106, 2 months ago

a³(2-a)-a²(a-3)+6a(a+4)​

Answers

Answered by arishithasree
1

Answer:

-1a^4+a^3+9a^2+24a

Step-by-step explanation:

= a^3(2-a)-1a^2(a-3)+6a(a+4)

= a^3(-a-2)-1a^2(a-3)+6a(a-4)

= -1a^4+2a^3-1a^2(a-3)+6a(a+4)

= -1a^4+2a^3-1a^3+3a^2+6a(a-4)

= -1a^4+2a^3-1a^3+3a^2+6a^2+24a

= -1a^4+1a^3+3a^2+6a^2+24a

now combined like terms

=. -1a^5+a^3+9a^2+24a

Answered by kumarjayakishan
0

Answer:

g

Step-by-step explanation:

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