Question

a³-2a²b+2ab²+b³,a³+b³,a⁴+b⁴find it's LCM​

Answer 1

Answer:

(a³-b³)(a+b²)= (a-b)(a²+ab+b²)

(a⁴-b⁴)= (a+b)(a-b)(a²+b²)

(3a⁴+2a³b-5a²b²)= a²(3a²+2ab-5b²)

= a²(3a²-3ab+5ab-5b²)

= a²{3a(a-b)+5b(a-b)}

= a²(a-b)(3a+5b)

as (a-b) is common in all the factors so HCF is (a-b)

and LCM is rest potions along with a-b, = a²(a-b)(a+b)(3a+5b)(a²+b²)(a²+ab+b²)

Step-by-step explanation:

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