Math, asked by pdas249, 7 months ago

a³ + 3a²b+ 3ab² + b³-8

Answers

Answered by kings07

14

A³+3a²b+3ab²+b³=(a+b)³
8=2³
a³-b³=(a-b)(a²+ab+b²)
(a+b)³-2³
=(a+b-2)((a+b)²+(a+b)2+2²)
=(a+b-2)(a²+b²+2ab+2a+2b+4)

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