a³+3a²b+3ab²+b³-8 solution
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a³+3a²b+3ab²+b³=(a+b)³
8=2³
a³-b³=(a-b)(a²+ab+b²)
(a+b)³-2³
=(a+b-2)((a+b)²+(a+b)2+2²)
=(a+b-2)(a²+b²+2ab+2a+2b+4)
8=2³
a³-b³=(a-b)(a²+ab+b²)
(a+b)³-2³
=(a+b-2)((a+b)²+(a+b)2+2²)
=(a+b-2)(a²+b²+2ab+2a+2b+4)
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