a3-3a2b+3ab2-b3 is divided by (a-b) then remainder is?
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The remainder when a³ - 3 a²b + 3 ab² - b³ is divided by ( a - b ) is equal to zero.
Given: a³ -3 a²b + 3 ab² - b³ is divided by ( a - b ).
To Find: The remainder when a³ - 3 a²b + 3 ab² - b³ is divided by ( a - b ).
Solution:
When we see the expression a³ - 3 a²b + 3 ab² - b³, we get reminded of the formula for ( a - b )³.
( a - b )³ = a³ - b³ - 3 ab ( a - b )
= a³ - 3 a²b + 3 ab² - b³
So, when ( a - b )³ is divided by ( a - b ), the remainder must be zero and the quotient must be ( a - b )² or a² - 2 ab + b².
Hence, the remainder when a³ - 3 a²b + 3 ab² - b³ is divided by ( a - b ) is equal to zero.
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