Question

a3 + 64 (Factoriseit maths) ​

Answer 1

Answer:

Theory : A difference of two perfect cubes, a3 - b3 can be factored into

(a-b) • (a2 +ab +b2)

Proof : (a-b)•(a2+ab+b2) =

a3+a2b+ab2-ba2-b2a-b3 =

a3+(a2b-ba2)+(ab2-b2a)-b3 =

a3+0+0-b3 =

a3-b3

Check : 64 is the cube of 4

Check : a3 is the cube of a1

Factorization is :

(a - 4) • (a2 + 4a + 16)

Answer 2

Step-by-step explanation:

x3+64=x3+43 

We know that the sum of two cubes, x3+y3=(x+y)(x2−xy+y2)

So, x3+43=(x+4)(x2−4x+42)

x3+43=(x+4)(x2−4x+16)