a³-8b³-64c³-24abc factorize it
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(a)^3+(-2b)^3+(-4c)^3-3(a)(-2b)(-4c)=(a-2b-4c)
[a^2+(-2b)^2+(-4c)^2-(a)(-2b)-(-2b)(-4c)-(-4c)(a)]
=(a-2b-4c)(a^2+4b^2+16c^2+2ab-8bc+4ca)
[a^2+(-2b)^2+(-4c)^2-(a)(-2b)-(-2b)(-4c)-(-4c)(a)]
=(a-2b-4c)(a^2+4b^2+16c^2+2ab-8bc+4ca)
brijeshupadhyay77:
hope this will help you
thanku for taking this answer as brainliat
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