Question

a³-8b³-64c³-24abc please factorize it​

Answer 1

Solution:

We know the algebraic identity:

/* x³+y³+z³ -3xyz =

(x+y+z)(x²+y²+z²-xy-yz-zx) */

Now ,

a³-8b³-64c³-24abc

=a³+(-2b)³+(-4c)³-3*a*(-2b)(-4c)

=[a+(-2b)+(-4c)][a²+(-2b)²+(-4c)²-a(-2b)-(-2b)(-4c)-(-4c)a]

=(a-2b-4c)(a²+4b²+16c²+2ab-8bc+4ca)

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Answer 2

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