Question

{a³-(a-2)(a²-a-42)} divide (a²+6a)​

Answer 1

Answer:

I hope the given answer will help you

Answer 2

SOLUTION

TO EVALUATE

$\displaystyle \sf{ \frac{\{ {a}^{3} - (a - 2 ) \}( {a}^{2} - a - 42) }{ {a}^{2} + 6a} }$

EVALUATION

$\displaystyle \sf{ \frac{\{ {a}^{3} - (a - 2 ) \}( {a}^{2} - a - 42) }{ {a}^{2} + 6a} }$

$\displaystyle \sf{ = \frac{\{ {a}^{3} - a + 2 \}( {a}^{2} - a - 42) }{ {a}^{2} + 6a} }$

$\displaystyle \sf{ = \frac{\{ {a}^{3} - a + 2 \} \{ {a}^{2} - (7 - 6)a - 42 \}}{ {a}^{2} + 6a} }$

$\displaystyle \sf{ = \frac{\{ {a}^{3} - a + 2 \} \{ {a}^{2} - 7a + 6a - 42 \}}{ {a}^{2} + 6a} }$

$\displaystyle \sf{ = \frac{\{ {a}^{3} - a + 2 \} \{a(a - 7) + 6(a - 7) \}}{ {a}^{2} + 6a} }$

$\displaystyle \sf{ = \frac{\{ {a}^{3} - a + 2 \} \{(a - 7) (a + 6) \}}{ a(a + 6)} }$

$\displaystyle \sf{ = \frac{\{ {a}^{3} - a + 2 \}(a - 7) }{ a} }$

$\displaystyle \sf{ = \frac{(a - 7) ({a}^{3} - a + 2 )}{ a} }$

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