Math, asked by AdarshGautam, 1 year ago

a3-a2b+1/3ab2-1/27b3 factorise

Answers

Answered by mysticd
3

Answer:


Step-by-step explanation:

a³-a²b+(1/3)ab²-(1/27)b³

= a³ - 3×a²×(b/3) + 3×a×(b/3)² - (b/3)³

= ( a - 3/b )³

= ( a-3/b)(a-3/b)(a-3/b)

....


AdarshGautam: thanks you very much
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