a3-a2b+1/3ab2-1/27b3 factorise
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Answer:
Step-by-step explanation:
a³-a²b+(1/3)ab²-(1/27)b³
= a³ - 3×a²×(b/3) + 3×a×(b/3)² - (b/3)³
= ( a - 3/b )³
= ( a-3/b)(a-3/b)(a-3/b)
....
AdarshGautam:
thanks you very much
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