a3 b-a2 b +5ab-5b. factorize
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we have to factorise the expression,
a³b - a²b + 5ab - 5b
solution : a³b - a²b + 5ab- 5b
= a²b × a - a²b × 1 + 5b × a - 5b × 1
= a²b(a - 1) + 5b(a - 1)
= (a²b + 5b)(a - 1)
= {a² × b + 5 × b} (a - 1)
= {b(a² + 5)}(a - 1)
= b(a² + 5)(a - 1)
Therefore the factorisation of a³b - a²b + 5ab - 5b is b(a² + 5)(a -1).
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