Question

a³+b³=16 and(a+b)³=64 then find ab​

Answer 1

answer comes out to be 4 .

if u find my answer useful then mark me as brainlist

Answer 2

ANSWER--->

A/C,

${(a + b)}^{3} = 64 \\ a + b = \sqrt[3]{64} \\ a + b = 4 \: \: \: \: \: \: |1|$

ALSO, BY USING IDENTITY;

${(a + b)}^{3} = {a}^{3} + 3ab( a + b) + {b}^{3}$

$putting \: {a}^{3} + {b}^{3} = 16 \\ \\ 64 = 16 + 3(a b) \\ 64 - 16 = 3ab(a + b) \\ \frac{12}{3} = ab \\ ab = 4$

HENCE,

ab=4