Question

a3+b3+3ab2+3a2b if a=2 and b = -3

Answer 1

a³ + b³ + 3ab² + 3a²b


There are two ways. One way is that you directly put the values.

(2)³ + (-3)³ + 3(2)(-3)² + 3(2)²(-3)

=> 8 - 27 + 54 - 36

=> 62 - 63

= -1


Another and more efficient way is that you apply the identity

a³ + b³ + 3ab² + 3a²b = (a + b)³

Now just put the values in (a + b)³

=> (2 - 3)³

= (-1)³

= -1


I suggest you the second way,

Answer 2

Answer:(-1)

Step-by-step explanation:

This is the formula for ${(a+b)}^{3}$

Therefore, ${(2-3)}^{3}$ =${-1}^{3}$=-1