(a³+b³)
(a+b)³
formulae
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Answer:
Step-by-step explanation:a³-b³=(a-b)(a²+ab+b²)
Proof
We know
(a-b)³=a³-b³-3a²b+3b²a
a³-b³=(a-b)³+3a²b-3b²a
a³-b³=(a-b)³+3ab(a-b)
Taking (a-b) common
a³-b³=(a-b)((a-b)²+3ab)
Using indentity (a-b)²=a²+b²-2ab
a³-b³=(a-b)(a²+b²-2ab+3ab)
Therefore a³-b³=(a-b)(a²+b²+ab)
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