Math, asked by bimalkrsingha486, 1 day ago

(a³+b³)
(a+b)³
formulae​

Answers

Answered by AaronThomas20091975
1

Answer:

Step-by-step explanation:a³-b³=(a-b)(a²+ab+b²)

Proof

We know

(a-b)³=a³-b³-3a²b+3b²a

a³-b³=(a-b)³+3a²b-3b²a

a³-b³=(a-b)³+3ab(a-b)

Taking (a-b) common

a³-b³=(a-b)((a-b)²+3ab)

Using indentity (a-b)²=a²+b²-2ab

a³-b³=(a-b)(a²+b²-2ab+3ab)

Therefore a³-b³=(a-b)(a²+b²+ab)

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