Question

a3 + b3 + c(a²-ab+b 2)​

Answer 1

Answer:

(a+b) ^3=a^3+b^3+3ab(a+b)

(a+b) ^3=a^3+b^3+3ab(a+b)(a+b) ^3–3ab(a+b) =a^3+b^3

(a+b) ^3=a^3+b^3+3ab(a+b)(a+b) ^3–3ab(a+b) =a^3+b^3(a+b) {(a+b) ^2–3ab) }=a^3+b^3

(a+b) ^3=a^3+b^3+3ab(a+b)(a+b) ^3–3ab(a+b) =a^3+b^3(a+b) {(a+b) ^2–3ab) }=a^3+b^3(a+b) (a^2+2ab+b^2–3ab) =a^3+b^3

(a+b) ^3=a^3+b^3+3ab(a+b)(a+b) ^3–3ab(a+b) =a^3+b^3(a+b) {(a+b) ^2–3ab) }=a^3+b^3(a+b) (a^2+2ab+b^2–3ab) =a^3+b^3(a+b) (a^2-ab+b^2) =a^3+b^3

Answer 2

see the attached image hope it helps to you