Math, asked by namahimamnaz, 1 year ago

a³ - b³ - c³ - 3abc =

Answers

Answered by arnav98
3
a³ - b³ - c³ - 3 abc = (a + b + c)(a² + b² + c² − ab − bc − ca)

arnav98: mark my best
Answered by pahiroy1221
3
a^3-b^3-c^3-3abc = ( a+b+c ) ( a^2 + b^2 + c^2 - ab - bc - ca )
   i hope that this will help u..................^_^
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