Question

a3 + b3 + c3 _ 3abe, when a=-4, b = -6) (= -2​

Answer 1

Answer:

4 (3)+ (-6)(3)+(-2)(3)

12-18-6

12-24

-12

Answer 2

${a}^{3} + {b}^{3} + {c}^{3} - 3abc \\ \\ a = - 4 \\ b = - 6\\ c = - 2 \\ \\ = ({ - 4}^{3} )+ ({ - 6}^{3} ) + ({ - 2}^{3} ) + 3( - 4 \times - 6 \times - 2) \\ = - 64 - 216 - 8 - (48 \times 3) \\ = - 432$

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