Question

{a³+b³+c³+a²(b+c)+b²(c+a)+c²(a+b)}÷(a²+b²+c²)

Answer 1

Answer:

5

Step-by-step explanation:

a^3+b^c^3 -3abc =(a+b+c)(a^2+b^2+c^2-ab-bc-ca)

Given ab+bc+ca=6,

Multiplying by 2 on both sides

2(ab+bc+ca)=12,……….(2)

a^2+b^2+c^2=13

Applying formula

(a+b+c)^2= (a^2+b^2+c^2 +2ab+2bc+2ca)

Putting the values a^2+b^2+c^2 and (ab+ bc+ca) on right hand side

=13 +2(ab+bc+ ca)

= 13+12

=25

(a+b+c)^2 =25,taking square root on both sides.

(a+b+c)= 5.

Putting the values in eq 1

=5×(13–12)

=5.