Question

A3 For what wahur K, the quadrstic equation
Kx(x-2)=0 has real roots?​

Answer 1

Answer:

the given equation can be written in the form of

$k {x}^{2} - 2kx + 6 = 0$

now it has equal roots that means The Discriminant is 0

D = 0

Also

${b}^{2} - 4ac = 0 \\ {4k}^{2} - 4(k)(6) = 0 \\ 4 {k}^{2} - 24k = 0 \\ 4k(k - 6) = 0 \\ k - 6 = 0 \\ k = 6$

Hence the value of K is 6.