Math, asked by anandkumarp377, 22 hours ago

a3b2c2-ab2c3+a2b3c a


nswer

Answers

Answered by navithukulasekara
0

Answer:

ab2c3 = a × b2 × c3. a2b3c = a2 × b3 × c. a3bc2 = a3 × b × c2. G.C.D = abc.

Step-by-step explanation:

Highest Common Factor.

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