Question

a⁴-22a²b²+121b⁴-289 factorise​

Answer 1

${a}^{4} - 22 {a}^{2} {b}^{2} + {121b}^{4} - 289$

solulution=

1. $( {a}^{2} ) ^{2} - 2 \times {a}^{2} \times ( {11b}^{2} ) ^{2} + ({11b}^{2} ) ^{2} - 289$
2. $( {a}^{2} - 11 {b}^{2}) ^{2} - (17) ^{2}$
3. $(a ^{2} - 11 {b}^{2} + 17) \\ ( {a}^{2} - 11 {b}^{2} - 17)$