Question

a4-2a2b2+b4
Factorise. ​

Answer 1

Answer:

a2-b2

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Step-by-step explanation:

(a2)2 -2(a2b2)+(b2)2

a2-b2

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Answer 2

$\Huge{\textbf{\textsf{\color{orange}{An}{\purple{sw}{\pink{er}{\color{pink}{:}}}}}}}$

$\bf{{\underline{To~solve}}:}$

$\sf{a^{4}-2a^{2}b^{2}+b^{4}}$

$\bf{{\underline{Solution}}:}$

${\sf{\pmb{\underline{Identity}}:}}~$

${\sf{(a)^{2}-2ab+(b)^{2}=(a-b)(a-b)=(a-b)^{2}}}$

$\sf\implies{(a^{2})^{2}-2(a^{2})(b^{2})+(b^{2})^{2}}$

$\sf\implies{(a^{2}-b^{2})(a^{2}-b^{2})}$

$\sf\implies{{\purple{\underline{\boxed{\bf (a^{2}-b^{2})^{2}}}}}}$

$\bf\therefore{{\underline{Required~answer}}:}$

$\sf{a^4}-2a^{2}b^{2}+b^{4}$

${\purple{\underline{\underline{\bf (a^2}-b^{2})^{2}}}}$