Question

a4-2a2b2+b4 please tell tomorrow is my paper​

Answer 1

Step-by-step explanation:

=a⁴-2a²b²+b4

=(a²)²-2(a²)(b²)+(b²)

=(a²-b²)²

=[(a+b)(a-b)]²

Answer 2

$\huge\rm\purple{an{\mathfrak{S}}wer:}$

${}$

$\bf{{\underline{To~solve}}:}$

• $\sf{a^{4}-2a^{2}b^{2}+b^{4}}$

$\bf{{\underline{Solution}}:}$

${\sf{\pmb{\underline{Identity}}:}}~{\sf{(a)^{2}-2ab+(b)^{2}=(a-b)(a-b)=(a-b)^{2}}}$

$\sf\implies{(a^{2})^{2}-2(a^{2})(b^{2})+(b^{2})^{2}}$

$\sf\implies{(a^{2}-b^{2})(a^{2}-b^{2})}$

$\sf\implies{{\purple{\underline{\boxed{\bf (a^{2}-b^{2})^{2}}}}}}$

$\bf\therefore{{\underline{Required~answer}}:}$

• $\sf{a^{4}-2a^{2}b^{2}+b^{4}={\purple{\underline{\underline{\bf (a^{2}-b^{2})^{2}}}}}}$