Question

a⁴+4a²-5 convert into factor​

Answer 1

Answer:

2.1 Factoring a4+4a2-5

The first term is, a4 its coefficient is 1 .

The middle term is, +4a2 its coefficient is 4 .

The last term, "the constant", is -5

Step-1 : Multiply the coefficient of the first term by the constant 1 • -5 = -5

Step-2 : Find two factors of -5 whose sum equals the coefficient of the middle term, which is 4 .

-5 + 1 = -4

-1 + 5 = 4 That's it

Step-3 : Rewrite the polynomial splitting the middle term using the two factors found in step 2 above, -1 and 5

a4 - 1a2 + 5a2 - 5

Step-4 : Add up the first 2 terms, pulling out like factors :

a2 • (a2-1)

Add up the last 2 terms, pulling out common factors :

5 • (a2-1)

Step-5 : Add up the four terms of step 4 :

(a2+5) • (a2-1)

Which is the desired factorization

hope it helps you

Answer 2

Question :

$\huge\bf\red{a^4-4a^2-5}$

Answer :

✢The first term is, $\sf{a^4}$ its coefficient is 1.

✢The middle term is, $\sf{-4a^2}$ its coefficient is -4.

✢The last term, "the constant", is -5.

Now ;

✢Let's multiply the coefficient of the first term by the constant ;

• 1×(-5)= -5

✢Find two factors of (-5) whose sum equals the coefficient of the middle term, which is (-4).

• (-5)+1= -4

• $\sf{a^4-5a^2+1a^2-5}$

• $\sf{a^2×(a^2-5)}$

• $\sf{1×(a^2-5)}$

Now ;

$\sf{(a^2+1)×(a^2-5)}$

$\huge\sf\blue{Hence~Factorised}$