a4+a2b2+b4/b4+b2c2+c4=a2/c2
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If b is the mean proportion between a and c, we have to prove LHS=RHS -
- If b is the mean proportion between a and c as given, it would imply - a/b = b/c = b²=ac (1)
- Left Hand Side = (a²)² +a²b²+(b²)² / (b²)²+b²c²+(c²)²
- Right Hand Side = a²/c²
- Therefore, (a²)² + a³c + a²c² / a²c² + ac³ + (c²)² (substituting value of b² from 1)
- a² (a²+ac+c²) / c² (a²+ac+c²) = a²/c² = Right Hand Side
- Hence, proved.
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