Question

(a4-a3+a2-a+1)÷(a3-2)
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Answer 1

I Hope u understand!

Answer 2

step 1 pull out like factors

a4+a3-a2-a

a.(a3+a2-a-1)

checking for a perfect cube

a3+a2-a-1 is not a perfect cube

trying to factor by pulling out

factoring a3 +a2-a-1

thoughtfully split the expression at hand into groups each group having two terms

group 1:-a-1

group 2:a3+a2

pull out from each group seperatly :

group 1:(a+1).(-1)

group 2 :a+1 .a2

add up the two groups

trying to factors as a difference of squares

factoring :a2-1

theory : a difference of two perfect squares a2-b2 can be factored into a+b .a-b

proof a+b .a-b =

a2-ab +ba-b2=

a2-ab+ab -b2=

a2-b2

note ab =ba is commutative property of multiplication

note -ab+ab equals zero is therefore eliminated from the expression

check :1 is th square of 1

check:a2 is the square of a1

factorization is a+1.a1

multiplyiing xponnential expression

multiply a+1 by a+1

final result. a+1square . a - 1

plz mark as the brainliest answer