Question

A⁴={b:b€Z' and -7<3b-1<or=2}

Answer 1

sdaffffffffffffffffffffffffffffffffffffssfsdfacdf fd

Answer 2

Given:

$\bold{A^4= \{ b:b \in Z' \ and -7 < 3b-1< or = 2 \}}$

To prove:

Find the value of $A^4$.

Solution:

$\Rightarrow \bold{A^4= \{ b:b \in Z' \ and -7 < 3b-1< or = 2 \}}$

solve equation:

         $= -7 < 3b-1< or = 2$    .................add  1 in the above value,

         $= -7+1 < 3b-1+1< or = 2+1 \\\\= -6 < 3b< or = 3\\\\= -2 < b< or = 1$

in this equation -2 is  not count so the value of b is -1, 0, 1

$A^4 = \{ b\}$

So, $\ A = \ 0, \pm 1, \ and \ \pm \sqrt{i}$

The value of = $\bold{\ A = \ 0, \pm 1, \ and \ \pm \sqrt{i}}$