Question

a⁴+b⁴-7a²b² factorisation​

Answer 1

Answer:

(a²+b²+3ab) (a²+b²-3ab)

Step-by-step explanation:

the question is a⁴+b⁴-7a²b²

now,

= (a²)²+(b²)²-7a²b²

using the identity, a²+b²=(a+b) ²-2ab

=(a+b) ²-2a²b²-7a²b²

=(a+b)²-9a²b²

=(a+b)²-(3ab)²

using the identity,a²-b²=(a+b) (a-b)

(a²+b²+3ab) (a²+b²-3ab) [Answer]

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