English, asked by devendragajjar1, 23 hours ago

a⁴×b⁵×c⁷
———––
c⁸×a⁴×b³​

Answers

Answered by pradipdhawal0
1

Answer:

(a^4×b^5×c^7)/(c^8×a^4×b^3)

=a^4-4×b^5-3×c^7-8

=a^0×b^2×c^-1

=b^2/c

Answered by pinakiparbatihembram
1

Explanation:

a^4 × b^5 × c^7

a^4 × b^3 × c^8

= a^4-4 × b^5-3 × c^7-8

= a^0 × b^2 × c^-1 (a^0=1; 1× b^2×c^-1= b^2×c^-1)

= b^2/c (Ans). (b^2×c^-1= b^2×1/c)

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