Question

a4273b is a six digit number in which a and b are digit the number is divisible by 72 then 2a-b =4 prove​

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If A679B is a 5 digit number is divisible by 72 find

′

A

′

and

′

B

′

?

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First we have to break 72 into factors 9,8

Now,

(i) Divisibility Rule of 8 is that the last three digits should be divisible by 8

and

(ii) Divisibility Rule of 9 is that the sum of digits must be divisible by 9

So, 79B must be divisible by 8 and only B=2 is satisfying the condition

Now, using (ii) we get, A+6+7+9+2=9α (multiple of 9)

A=9α−24 only α=3 is satisfying by hit and trial method

So. A=27−24=3

Therefore, A=3,B=2