Math, asked by Maddhy3312, 1 month ago

a4273b is a six digit number in which a and b are digits. This number is divisible by 72 then

Answers

Answered by Avishi123
11

Answer: b=6, a=5

Step-by-step explanation:

For a number to be divisible by 72, it should be divisible by both 8 and 9.

1) Divisibility by 8

For a number to be divisible by 8, the last three digits of the number should be divisible by 8, so 73b should be divisible by 8.

Now dividing, 73b by 8, we get remaining 1b. So, we need to keep such a value that it becomes a divisible of 8, so b =6. So it becomes 16 and hence 736 is divisible by 8.

Thus, b = 6

2) Divisibility by 9

For a number to be divisible by 9, sum of all its digits should be divisible by 9.

=a+4+2+7+3+b

= a+ 4+2+7+3+6        (As b=6)

= a+ 22

We need to add a number to 22, after which it becomes a multiple of 9. So, a = 5, as 5+22 = 27, which is a multiple of 9.

Thus, a = 5

Hope it helps!!

Answered by nikhilkumar7882
1

Answer:

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