Math, asked by snehasarkar01, 9 months ago

(a4b2-a2b4-a4b4)÷a2b2 using factorization method

Answers

Answered by amanatamema140751

0

Answer:

-b2

Step-by-step explanation:

a4b4-a4b4= 0

Thus, -a2b4/a2b2= -b2

Answered by babyrai081gmailcom

1

Answer:

a2-b2-a2b2

Step-by-step explanation:

a2b2(a2-b2-a2b2)/a2b2

=a2-b2-a2b2

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