Question

a5=23,s10=255 so find d and a10​

Answer 1

Answer:

a5=23, S10=255, d=?, a10=?

a5=a+4d=23.

a=23-4d.

Sn=n/2[2a+(n-1)d].

S10=10/2[2(23-4d)+(10-1)d]=255.

=5[46-8d+9d]=255.

=5[46+1d]=255.

230+5d=255.

5d=255-230.

5d=25.

d=25/5.

d=5.

substituting the value of 'd'.

a=23-4d.

a=23-4(5).

a=23-20.

a=3.

a10=a+9d.

=3+9(5).

=3+45.

a10=48.

I think this is your answer. Please mark it as brainliest if you think.